Suppose
we have to multiply two consecutive numbers say n and n+1
then n x (n+1) = n2 + n
If we take it in the reverse way, say (n-1) and n
then (n-1) x n = n2 – n
We can apply this for speed calculation,
then n x (n+1) = n2 + n
If we take it in the reverse way, say (n-1) and n
then (n-1) x n = n2 – n
We can apply this for speed calculation,